jpa - Transform SQL statement into JPQL to get latest entries for each user -

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i want transform sql statement

select * (select * `votes` order `date` desc) sub group `username`

into jpql. idea latest vote (order date desc) each user (group username).

i understand jpql not support subqueries in from, tried "in"

# not work! select v vote v v.id in (select tmp.id vote tmp order date desc) group v.username

but gives me first entries. tried "max"

# not work! select v vote v v.date in (select max(tmp.date) vote tmp group tmp.username)

as well, gives me multiple entries of same user date not unique...

edit:

i thought of creating view sql syntax workaround, jpql query refers class (not table) didn't me far ;-)

edit:

then thought of joins , lead me native queries. turns out can use above sql nativequery = true:

@query(value = "select * (select * `votes` order `date` desc) sub group `username`", nativequery = true)

and works!

see final update: can use initial sql statement if use nativequery = true - of course code not portable then, native queries bound (current) database type

thanks!


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