sql - Only want the first if several matches are returned -

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i have sql script returns number of records. code:

select distinct eb.exerciseindex, eb.exercisestarttime, avg(pb.playerbirthyear) birthavg, count(pb.playerindex) playersinexercise, pb.playersex playerbase pb inner join exbase ex on ex.explayerindex = pb.playerindex inner join exercisebase eb on eb.exerciseindex = ex.exexerciseindex exerciseallowanceindex='b26e10c5-53e1-413a-8a49-a7088d33e690' , exercise_is_paying='true' group exercisestarttime, pb.playersex, eb.exerciseindex  order exerciseindex, playersinexercise desc

i have attached image results.

now, want kind of distinct on results. if note, on occasions several rows returned same exerciseindex (see row 1 , 2 example). need first row exerciseindex returned (the 1 higher playercount).

any ideas how can done?

regards,

bob

returned sql

you should neat little so-called window function called row_number.

using this, like:

select * (     select *,          row_number() on (partition exerciseindex order playersinexercise desc) n     (         -- original query goes here - except order clause --     ) t1 ) t2 t2.n = 1 -- put order clause here --

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