Optionally pass argument to subprocess in python -

in script call executable optional command line argument (if passed, argument switches on function in executable, off default). want control option directly argument of script itself. write do:

import subprocess option = false if option:     check = subprocess.popen(['executable', '--option']) else:     check = subprocess.popen(['executable']) 

i tried find more compact way:

import subprocess option = false check = subprocess.popen(['executable', '--option' if option else '']) 

but raises error "unknown option" in exactable itself.

and raises error in python:

import subprocess option = false check = subprocess.popen(['executable', '--option' if option else none]) 

so, question: there way pass optional argument subprocess in 1 line?

using list slicing:

>>> ['executable', '--option'][:1 + false] ['executable'] >>> ['executable', '--option'][:1 + true] ['executable', '--option']  >>> false == 0 true >>> true == 1 true 

---

check = subprocess.popen(['executable', '--option'][:1 + option]) 

update alternative

you can use list * bool:

>>> ['a'] * true ['a'] >>> ['a'] * false [] 

using this, can combine multiple options:

check = subprocess.popen(['executable'] +                          ['-option1'] * option1 +                          ['-option2'] * option2)