Change ISO Date String to Date Object - JavaScript -

i stuck in weird situation , unfortunately,even after doing rnd , googling, unable solve problem.

i have date string in iso format, 2014-11-03t19:38:34.203z , want convert date object new date() method.

but when so, output is:

var isodate = '2014-11-03t19:38:34.203z'; console.log(new date(isodate)); //output is: tue nov 04 2014 01:08:34 gmt+0530 (ist) 

the date passed of 3 nov,2014 , output 4 nov,2014 , it's because of gmt +5.30 of our local time(ist).

so, there generic method can date object return date of nov 3,2014.

note: don't have issues timestamp. can change time string 0 sethours() method. thing want date object new date() having date of 3 nov,2014.

do not pass strings date constructor, notoriously bad @ parsing strings. ie 8, one, not parse iso 8601 format strings @ , return nan. it's simple write own parser:

function parseisostring(s) {   var b = s.split(/\d+/);   return new date(date.utc(b[0], --b[1], b[2], b[3], b[4], b[5], b[6])); } 

note if time 19:38:34.203 utc , timezone utc +0530, time in timezone 01:08:34 on following day, hence difference in dates. example, person on east coast of australia not observing daylight saving (i.e. utc +10), it's equivalent to:

4 november, 2014 05:38:34 

edit

so if want return iso date, can use getiso* methods create whatever format suits, e.g.

function isoformatdmy(d) {     function pad(n) {return (n<10? '0' :  '') + n}   return pad(d.getutcdate()) + '/' + pad(d.getutcmonth() + 1) + '/' + d.getutcfullyear(); }  var s = '2014-11-03t19:38:34.203z'; var date = parseisostring(s);  console.log(isoformatdmy(date)) // 03/11/2014 

or use es5's toisostring:

 parseisostring('2014-11-03t19:38:34.203z').toisostring(); // 2014-11-03t19:38:34.203z 

a simple polyfill pre es5 browsers:

if (!date.prototype.toisostring) {    date.prototype.toisostring = function() {      var d = this;      // padding functions      function pad(n) {return (n<10? '0' :  '') + n}     function padd(n){return (n<100? '0' : '') + pad(n)}      return d.getutcfullyear() + '-' + pad(d.getutcmonth() + 1) + '-' + pad(d.getutcdate()) +            't' + pad(d.getutchours()) + ':' + pad(d.getutcminutes()) + ':' +             pad(d.getutcseconds()) + '.' + padd(d.getmilliseconds()) + 'z';   } }