Python 3x class methods -

i'm learning basics of classes, , came basic code follows:

class shape(object):     def __init__(self, num_sides, type):         self.num_sides = num_sides         self.type = type  class square(shape):     def __init__(self, side_length):         self.num_sides = 4         self.type = 'regular quadrilateral'         self.side_length = side_length     def perim():         return side_length * 4     def area():         return side_length ** 2  class circle(shape):     def __init__(self, radius):         self.num_sides = 1         self.type = 'ellipsis'         self.radius = radius 

now, when type following:

shape1 = square(5) shape1.perim() 

i following output:

<bound method square.perim of <__main__.square object @ 0x0000000003d5fb38>> 

what this? how can python return perimeter of square?

also, have question: class methods exist other __init__() , __str__()? if so, can please list them can go off , research them?

as shown, going have problems this. if trying have circle , square subset set classes of shape, 2 sub classes need indented. also, on class circle , square, not need (shape). note things commented out not needed.

this not come out posting it. class shape (object):does not show , subclasses not indented , can not seem make show up

class shape(object): def init(self, num_sides, type): #self.num_sides = num_sides self.type = type

class square:      def __init__(self, side_length):         #self.num_sides = 4         #self.type = 'regular quadrilateral'         self.side_length = side_length      def perim(self):         return self.side_length * 4     def area(self):         return self.side_length ** 2  class circle:      def __init__(self, radius):         #self.num_sides = 1         #self.type = 'ellipsis'         self.radius = radius      def area (self):         return 3.14 * self.radius ** 2    shape2 = circle (5) print ('test of circle: ',shape2.area ())  shape1 = square(5) print('test of square:  ', shape1.perim())