sql - mysql query hierarchic -

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i need find sql query

create table album (     id_album integer not null primary key auto_increment,     nom varchar(255) not null );  create table sous_album (     id_sous_album integer not null primary key auto_increment,     nom varchar(255) not null,     id_album integer references album(id_album) );  create table photo (     id_photo integer not null primary key auto_increment,     nom varchar(255) not null,     id_sous_album integer references sous_album(id_sous_album) );  insert album(id_album, nom) values ('1', 'album1'), ('2', 'album2'), ('3', 'album3') ;  insert sous_album(id_sous_album, nom, id_album) values ('1', 'sous album 1', '1'), ('2', 'sous album 2', '1'), ('3', 'sous album 3', '1'), ('4', 'sous album 4', '2'), ('5', 'sous album 5', '2'), ('6', 'sous album 6', '3') ;  insert photo(id_photo, nom, id_sous_album) values ('1', 'photo1', '1'), ('2', 'photo2', '1'), ('3', 'photo3', '1'), ('4', 'photo4', '1'), ('5', 'photo5', '2'), ('6', 'photo6', '2'), ('7', 'photo7', '3'), ('8', 'photo8', '3'), ('9', 'photo9', '3'), ('10', 'photo10', '4'), ('11', 'photo11', '5'), ('12', 'photo12', '6'), ('13', 'photo13', '6'), ('14', 'photo14', '6'), ('15', 'photo15', '6') ;  select distinct  album.nom, count(photo.id_photo) album, photo, sous_album album.id_album=sous_album.id_album , sous_album.id_sous_album=photo.id_sous_album group album.nom order album.nom`

this query give me name of album , number of photos want sous album , numbers of photo... can u me ?

the result :

nom    | count(photo.id_photo) album1 | 9 album2 | 2 album3 | 4

i need result :

nom          | count(photo.id_photo) album1       | 9 sous album 1 | 4 sous album 2 | 2 sous album 3 | 3 album2       | 2 sous album 4 | 1 sous album 5 | 1 album3       | 4 sous album 6 | 4 

select x.*      , y.*         ( select a.nom              , count(*) total           album           join sous_album ap             on ap.id_album = a.id_album           join photo p             on p.id_sous_album = ap.id_sous_album         group             a.nom      ) x   join        ( select a.nom nom_album             , ap.nom nom_sous_ablum             , count(*) total           album           join sous_album ap             on ap.id_album = a.id_album           join photo p             on p.id_sous_album = ap.id_sous_album          group             a.nom             , ap.nom      ) y     on y.nom_album = x.nom;

note particular query return album if there @ least 1 sous_album (and photo) associated it.


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