java - Linked list creates infinte loop when outputted (No Iterators allowed) -

when user stores 2 or more values list, output displays this:

item 3: null item 4: null item 5: null ... item 14623: null 

this case when user wants output list

case output: {     system.out.println ("the list:");     displaylist();     break; } 

which leads displaylist() method

public static void displaylist() {     (int = 0; <= list.size (); i++)     {         system.out.println ("item " + + ": " + list.get(i));     } } 

which uses list.size()

public int size() {     for(node n = header; n.getnext() != null; n = n.getnext())     {         size++;     }     return size; } 

and list.get()

public object get(int index) {     node n = traverse(index);      if (n == null)     {         return null;     }     return n.getdata(); } 

getnext()

public node getnext() {     return next; } 

traverse(). think method what's causing problems

public node traverse(int index) {     node n = header;      if (index < 0)     {         return null;     }      (int indextwo = 0; indextwo < index; indextwo++)     {         if (n == null)         {             return null;         } // end of if (n == null)         n = n.getnext ();     }     return n; } 

this part never executed:

for (int indextwo = 0; indextwo < index; indextwo++)  

since index variable 0 , indextwo < index gives false. use:

for (int indextwo = 0; indextwo <= index; indextwo++)  

edit:

another issue in size() method:

public int size() {     for(node n = header; n.getnext() != null; n = n.getnext())     {         size++;     }     return size; } 

where increment size variable static? one. so, must have initialized elsewhere. guess need make local variable , initialize inside method. issue getnext() twice in each step:

for(node n = header; n.getnext() != null; n = n.getnext())

just check n not n.getnext() != null null.